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# Titration of a strong acid with a strong base (continued)

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- We've been looking
at the titration curve for the titration of a strong acid, HCl, with a strong base, NaOH. In the previous video, we've already found the pH at two points
on our titration curve, so we found the pH before
we'd added any of our base, we found the pH at this point, and we also found the pH after we added 10 mls of our base, we
found the pH at this point. This is Part A of our question, this is Part B of our question. Now we're on Part C. What is the pH after
the addition of 20 mls of a .500 molar solution
of sodium hydroxide? So how many moles of
hydroxide ions are we adding to our original acid solution? We can figure that out by
this concentration rate here. So the concentration of sodium
hydroxide is .500 molar. That's also the concentration
of hydroxide ions in solution, since we're talking about a strong base, so the concentration of
hydroxide ions in solution is equal to .500 molar. Remember: molarity is moles over liters. So this would be equal
to moles over liters. How many liters do we have? We have 20 milliliters, so 20
milliliters would be equal to, move our decimal place, one, two, three; that's .02 liters. So to find how many moles,
just multiply .5 by .02 and you will get .01 So we have .01 moles of hydroxide ions. So that's how many moles of
hydroxide ions we're adding to our original acid solution. In the previous video,
we already calculated the moles of hydronium ions in solution, and it was the same number
as this: .0100 moles of H3O+ So you could watch the previous video, or you can just look at,
it's the same numbers: 20 milliliters here, 20 milliliters here, .500 molar here, .500 molar here. So it's the same
calculation to give us moles of H3O+, hydronium, or you could just consider that to be moles of H+. So we have an equal number of moles of base as we do of acid, and the base that we're adding is going to neutralize the
acid that's present. So the H3O+, the hydronium that's present, is neutralized by the base that we add. And so H3O+ donates a proton
to OH-, so we get H2O, and then if H3O+ donates a proton, we also get another molecule of H2O. So we get two molecules of H2O here, and we are starting with .01 moles of OH- So let's go ahead and write that in here. So we have: .01 moles of base, and that's the same number of
moles of acid that we have. So .01 moles of acids. So, this time, we have enough base to completely neutralize our acids. So everything is reacting
in a 1:1 ratio here. So all of our base is going to react, and it's going to completely
neutralize our acids. So when that happens, the pH
should be just the pH of water. The pH of our solution
should be the pH of water, which we know is equal to seven, so 7.00 I could have written this another way. I could have written: HCl + NaOH, right? This would give us,
this would give us H2O, 'cause H+ and OH- give us H2O, and then we would have NaCl left, right? We would have a solution
of sodium chloride. So, an aqueous solution
of sodium chloride. And, if our acid and our base completely neutralize each other, we're just left with an aqueous solution
of sodium chloride, and so the pH is just the pH of water, because sodium and ions
and chloride anions don't interact with water
enough to change the pH. So the pH, after we've added 20 mls of our base, is equal to seven. So we can find that here
on our titration curve. So 20 mls of base added,
the pH should be seven, so we can find this point
on our titration curve. This is the equivalence point. So let me go ahead and
draw a line down here. So right here is our equivalence point. Let me write that. So, our equivalence
point has been reached. We've added enough moles of base to completely neutralize the acid present, so we've reached the equivalence point. Finally, in Part D, they
want us to find the pH after the addition of 20.2 mls of a .500 molar solution
of sodium hydroxide. So just like before, we need to find the moles of hydroxide ions that we're adding. And so the concentration of hydroxide ions is, once again, .5, so .500 molar. Molarity is moles over liters,
so we wanna find moles. How many liters are we adding? Well, 20.20 mls, is the
same thing as .02020 liters. So, we just need to solve for moles; and you can probably do this in your head. I'm just going to use the calculator here to show you the answer. So: .5 x .02020, gives us .0101 So that's how many moles
of hydroxide ions we have: .0101 moles of hydroxide ions. Okay, remember: the hydroxide ions reacted with the hydronium ions. We talked about the fact that
H3O+ plus OH- gives us 2H2O. This time, we're starting with .0101 moles of hydroxide ions. So let's write: .0101 moles. And hydronium, we only started
with .01 moles of hydronium, so, .01 moles of hydronium ions. And so, this time we have
more base than we do acid, so all of the acid is going
to be neutralized, right? So the acid is going to
be completely neutralized. We're gonna be left with nothing. So all the acid is gone, and most of the base is going to react. So we're gonna get the same,
we're gonna lose the same amount of base, so we're gonna
lose .0100 moles of base, and so we're left with a
very small amount of base. We're left with .0001
moles of base left over. So all of the acid has
been completely neutralized and we have a small
amount of base left over. Next, let's think about the total volume. We started with 20 mls of
our acid solution, right? We started our titration with 20 mls, and at this point of the titration, we've added 20.2 mls more. So we've added 20.2 mls more. This gives us a total volume of 40.20 mls. So we have 40.20 mls here. And now we can calculate the concentration of hydroxide ions in solution. So what's the concentration
of hydroxide ions? Concentration is moles over liters, and so we have .0001 moles of hydroxide, and the volume would be,
this is in milliliters, so that's the same thing as .04020 liters. So we can go ahead and
do that calculation. Take out the calculator here. So we have .0001 divided
by .04020, and we get .002 So our concentration of hydroxide ions is equal to .002 molar. Our goal was to find the pH, but right now, we just
have to find the pOH. So, the pOH is equal to the negative log of the concentration of hydroxide ions. So this is the negative log of .002 So: -log(.002) Let's see what that gives
us on the calculator. - log(.002) gives us a pOH of 2.7 So the pOH is equal to 2.7 And finally, to find the pH, we need to know one more equation. The pH plus the pOH is equal to 14. So if we plug in 2.7 into here, the pH is equal to 14 - 2.7,
which is, of course, 11.3 So we finally found the pH. So let's think about where this point is on our titration curve. We've added 20.20 mls of our base, let me go ahead and use blue for this so we can see it a little better, we've added 20.20 mls of our base, and the pH, we just found to be 11.3 So we're just barely past this 20 here. It's really hard to draw a straight line. I'm not doing a very good job. But our pH should be 11.3 so that allows us to find this
point on our titration curve, so somewhere around there.